A 5.00 gram bullet has a velocity of $300 \mathrm{~m} / \mathrm{s}$. It strikes a block of wood and penetrates to a depth of 2.00 $\mathrm{cm}$. The average force of the block of wood on the bullet is

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Quizplus · Accepted Answer

To find the average force, we can use the work-energy principle. The work done by the force is equal to the change in kinetic energy of the bullet. The kinetic energy (KE) of the bullet before it stops is given by $KE = \frac{1}{2}mv^2$, where $m = 0.005 \, \text{kg}$ (since 1 gram = 0.001 kg) and $v = 300 \, \text{m/s}$. The change in kinetic energy is equal to the work done by the force, $W = Fd$, where $F$ is the average force and $d = 0.02 \, \text{m}$ (since 1 cm = 0.01 m). Solving for $F$, we get $F = \frac{KE}{d}$. Substituting the values, we find $F = \frac{0.5 \times 0.005 \times 300^2}{0.02} = 11,250 \, \text{N}$.

A 500 Gram Bullet Has a Velocity Of Of 300 300 m/s300 \mathrm{~m} / \mathrm{s}300 m/s

A 500 Gram Bullet Has a Velocity Of Of 300 $300 \mathrm{~m} / \mathrm{s}$