A $2500 \mathrm{~kg}$ car accelerates from rest to a velocity of $30.0 \mathrm{~m} / \mathrm{s}$ in 8.00 seconds. The work done by the engine to accelerate the car is

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Quizplus · Accepted Answer

The work done by the engine can be calculated using the work-energy principle, which states that the work done is equal to the change in kinetic energy. The kinetic energy ($KE$) is given by $KE = \frac{1}{2}mv^2$, where $m$ is the mass and $v$ is the velocity. The initial kinetic energy is 0 (since the car starts from rest), and the final kinetic energy is $\frac{1}{2} \times 2500 \, \text{kg} \times (30.0 \, \text{m/s})^2 = 1.125 \times 10^6 \, \text{J}$. Therefore, the work done by the engine is $1.13 \times 10^6 \, \text{J}$.

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A $2500 \mathrm{~kg}$ Car Accelerates from Rest to a Velocity Of $30.0 \mathrm{~m} / \mathrm{s}$