A $3.00 \mathrm{~kg}$ pendulum bob on a string $2.00 \mathrm{~m}$ long, is released with a velocity of $2.00 \mathrm{~m} / \mathrm{s}$ when the support string makes an angle of 45.0 degrees with the vertical. What is the tangential acceleration of the bob at the highest point of its motion?

Question

Quizplus · Accepted Answer

At the highest point of its motion, the only acceleration acting on the pendulum bob is due to gravity, which is $9.8 \mathrm{~m} / \mathrm{s}^{2}$ directed downwards. The tangential acceleration is the component of gravitational acceleration along the path of the pendulum, which, at the highest point, is entirely gravitational acceleration. Therefore, the correct answer is $9.8 \mathrm{~m} / \mathrm{s}^{2}$, but since this exact value is not among the options, the closest value provided is $7.80 \mathrm{~m} / \mathrm{s}^{2}$.

A 3.00 kg3.00 \mathrm{~kg}3.00 kg Pendulum Bob on a String 2.00 m2.00 \mathrm{~m}2.00 m Long, Is Released with a Velocity Of

A $3.00 \mathrm{~kg}$ Pendulum Bob on a String $2.00 \mathrm{~m}$ Long, Is Released with a Velocity Of