Factor.
-$6 x^{2}-5 x t-4 t^{2}$
A) $(6 x+t)(x-4 t)$
B) Prime
C) $(2 \mathrm{x}+\mathrm{t})(3 \mathrm{x}-4 \mathrm{t})$
D) $(2 \mathrm{x}-\mathrm{t})(3 \mathrm{x}+4 \mathrm{t})$

Question

Quizplus · Accepted Answer

The correct factorization of $6x^2 - 5xt - 4t^2$ is obtained by finding two numbers that multiply to $6 \times -4 = -24$ and add to $-5$, which are $+3$ and $-8$. Rewriting the middle term $-5xt$ as $3xt - 8xt$ and factoring by grouping gives us $(2x + t)(3x - 4t)$.

Factor - 6x2−5xt−4t26 x^{2}-5 x t-4 t^{2}6x2−5xt−4t2 A) (6x+t)(x−4t)(6 x+t)(x-4 t)(6x+t)(x−4t) B) Prime C)

Factor
- $6 x^{2}-5 x t-4 t^{2}$ A) $(6 x+t)(x-4 t)$ B) Prime
C)