Factor.
-$20 x^{2}-23 x y+6 y^{2}$
A) $(4 x+3 y)(5 x-2 y)$
B) $(4 x-3 y)(5 x-2 y)$
C) $(20 x+3 y)(x+2 y)$
D) $(4 x+3 y)(5 x+2 y)$

Question

Quizplus · Accepted Answer

The correct factorization of $20 x^{2}-23 x y+6 y^{2}$ is found by looking for two numbers that multiply to $20*6=120$ and add to $-23$. These numbers are $-20$ and $-3$, allowing us to split the middle term and factor by grouping, leading to $(4 x-3 y)(5 x-2 y)$.

Factor - 20x2−23xy+6y220 x^{2}-23 x y+6 y^{2}20x2−23xy+6y2 A) (4x+3y)(5x−2y)(4 x+3 y)(5 x-2 y)(4x+3y)(5x−2y)

Factor
- $20 x^{2}-23 x y+6 y^{2}$ A) $(4 x+3 y)(5 x-2 y)$