Factor completely.
-$9 x^{2}+18 x+8$
A) $(3 x-2)(3 x-4)$
B) $(3 x+2)(3 x+4)$
C) $(9 x+2)(x+4)$
D) $(9 \mathrm{x}+1)(\mathrm{x}+8)$

Question

Quizplus · Accepted Answer

The correct factorization of $9x^2 + 18x + 8$ is obtained by finding two numbers that multiply to $9*8 = 72$ and add to $18$. These numbers are $2$ and $36$, which when factored back into the original quadratic equation, give us the factors $(3x + 2)(3x + 4)$.

Factor Completely 9x2+18x+89 x^{2}+18 x+89x2+18x+8 A) (3x−2)(3x−4)(3 x-2)(3 x-4)(3x−2)(3x−4) B) (3x+2)(3x+4)(3 x+2)(3 x+4)(3x+2)(3x+4)

Factor Completely $9 x^{2}+18 x+8$ A) $(3 x-2)(3 x-4)$ B) $(3 x+2)(3 x+4)$