Factor completely.
-$-36 x^{3}-33 x^{2}+45 x$
A) $x(-12 x+9)(3 x+5)$
B) $x(4 x-3)(-9 x-15)$
C) $-3\left(4 x^{2}-3\right)(3 x+5)$
D) $-3 x(4 x-3)(3 x+5)$

Name: Factor completely. -$-36 x^{3}-33 x^{2}+45 x$ A) $x(-12 x+9)(3 x+5)$ B) $x(4 x-3)(-9 x-15)$ C) $-3\left(4 x^{2}-3\right)(3 x+5)$ D) $-3 x(4 x-3)(3 x+5)$
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Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $-3x$, resulting in $-3x(12x^2+11x-15)$. Further factoring the quadratic expression gives $-3x(4x-3)(3x+5)$.

Factor Completely −36x3−33x2+45x-36 x^{3}-33 x^{2}+45 x−36x3−33x2+45x A) x(−12x+9)(3x+5)x(-12 x+9)(3 x+5)x(−12x+9)(3x+5) B) x(4x−3)(−9x−15)x(4 x-3)(-9 x-15)x(4x−3)(−9x−15)

Factor Completely $-36 x^{3}-33 x^{2}+45 x$ A) $x(-12 x+9)(3 x+5)$ B) $x(4 x-3)(-9 x-15)$