Solve the problem.
-The mass of a liquid varies directly as its volume $V$. If the mass of the liquid in a cubical container 3 $\mathrm{cm}$ on a side is $81 \mathrm{~g}$, find the mass of the liquid in a cubical container $5 \mathrm{~cm}$ on a side.
A) $15 \mathrm{~g}$
B) $125 \mathrm{~g}$
C) $375 \mathrm{~g}$
D) $110 \mathrm{~g}$

Question

Quizplus · Accepted Answer

The mass varies directly with volume, so $ m = kV $. For the 3 cm cube, $ V = 3^3 = 27 \, \mathrm{cm}^3 $ and $ m = 81 \, \mathrm{g} $, so $ k = \frac{81}{27} = 3 $. For the 5 cm cube, $ V = 5^3 = 125 \, \mathrm{cm}^3 $, so $ m = 3 \times 125 = 375 \, \mathrm{g} $.

Solve the Problem VVV If the Mass of the Liquid in a Cubical

Solve the Problem $V$ If the Mass of the Liquid in a Cubical