Solve the problem.
-The distance $D$ that a spring is stretched by a hanging object varies directly as the weight $W$ of the object. If a 11- $\mathrm{kg}$ object stretches a spring $53 \mathrm{~cm}$, find the distance when the weight is $22-\mathrm{kg}$.
A) $106 \mathrm{~cm}$
B) $86 \mathrm{~cm}$
C) $4.57 \mathrm{~cm}$
D) $4.82 \mathrm{~cm}$

Question

Quizplus · Accepted Answer

Since the distance $D$ varies directly as the weight $W$, we can use the proportion $\frac{D_1}{W_1} = \frac{D_2}{W_2}$. Given $D_1 = 53 \, \text{cm}$ and $W_1 = 11 \, \text{kg}$, for $W_2 = 22 \, \text{kg}$, solving for $D_2$ gives $D_2 = \frac{53 \, \text{cm} \times 22 \, \text{kg}}{11 \, \text{kg}} = 106 \, \text{cm}$.

Solve the Problem DDD That a Spring Is Stretched by a Hanging Object Varies

Solve the Problem $D$ That a Spring Is Stretched by a Hanging Object Varies