Solve the problem.
-The gravitational attraction A between two masses varies inversely as the square of the distance between them. The force of attraction is $4 \mathrm{lb}$ when the masses are $3 \mathrm{ft}$ apart, what is the attraction when the masses are $6 \mathrm{ft}$ apart?
A) $3 \mathrm{lb}$
B) $4 \mathrm{lb}$
C) $2 \mathrm{lb}$
D) $1 \mathrm{lb}$

Question

Quizplus · Accepted Answer

The gravitational attraction between two masses is given by $A = k/d^2$, where $k$ is a constant and $d$ is the distance between the masses. Given $A = 4$ lb when $d = 3$ ft, we find $k = 4 \times 3^2 = 36$. When $d = 6$ ft, $A = 36/6^2 = 36/36 = 1$ lb.

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