A mixture of 1.40 moles of A and 2.30 moles of B was allowed to reach equilibrium. At equilibrium, it is found that 0.90 mole of A is present. How many moles of C are present at equilibrium?
3 A (g) + 2 B (g) 4 C (g)
A) 1.60 moles
B) 0.667 mole
C) 1.10 moles
D) 1.30 moles
Correct Answer:
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