How will the pressure of a fixed sample of gas change if its volume is halved and its temperature is quadrupled (moles of gas remain constant)?

Question

Quizplus · Accepted Answer

Using the ideal gas law, $PV = nRT$, where $P$ is pressure, $V$ is volume, $n$ is moles of gas, $R$ is the gas constant, and $T$ is temperature. If the volume is halved ($V/2$) and the temperature is quadrupled ($4T$), the pressure changes by a factor of $(4T)/(V/2) = 8T/V$, meaning the pressure increases by a factor of 8.

How Will the Pressure of a Fixed Sample of Gas