A sample of N₂ gas occupies a volume 180 mL at STP. What volume, in L, will it occupy at 640 mm Hg and 295 K?

Question

Quizplus · Accepted Answer

The volume of the gas at the new conditions can be found using the combined gas law: $V_2 = \frac{P_1V_1T_2}{P_2T_1}$. At STP, $P_1 = 760$ mm Hg, $V_1 = 180$ mL or $0.180$ L, $T_1 = 273$ K, $P_2 = 640$ mm Hg, and $T_2 = 295$ K. Plugging these values into the formula gives $V_2 = \frac{760 \times 0.180 \times 295}{640 \times 273}$, which calculates to approximately $0.231$ L.

A Sample of N2 Gas Occupies a Volume 180 ML

A Sample of N₂ Gas Occupies a Volume 180 ML