How many Joules of heat must be removed to lower the temperature of a 36.5 g Al bar from 84.1 °C to 56.8 °C? The specific heat of Al is 0.908 J/g °C.

Question

Quizplus · Accepted Answer

The heat removed can be calculated using the formula q = mcΔT, where m is the mass (36.5 g), c is the specific heat (0.908 J/g°C), and ΔT is the change in temperature (84.1°C - 56.8°C = 27.3°C). Plugging in these values gives q = 36.5 g * 0.908 J/g°C * 27.3°C = 905 J.

How Many Joules of Heat Must Be Removed to Lower