What is the final temperature after 336 J of heat energy is removed from 25.0 g of water at 19.6 °C? Specific heat of water = 4.18 J/(g °C)

Question

Quizplus · Accepted Answer

The amount of heat energy (q) removed or added to a substance can be calculated using the formula q = mcΔT, where m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Rearranging the formula to solve for ΔT gives ΔT = q / (mc). Plugging in the given values: ΔT = -336 J / (25.0 g * 4.18 J/(g °C)) = -3.2 °C. Since the temperature decreases (heat is removed), the final temperature is 19.6 °C - 3.2 °C = 16.4 °C.

What Is the Final Temperature After 336 J of Heat