Four hypothetical elements, A, B, C and D, have the following electronegativities and periodic table positions:
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-How many "dots" would there be in the Lewis structure for the compound YW₂?

Question

Four hypothetical elements, A, B, C and D, have the following electronegativities and periodic table positions: ‪ -How many "dots" would there be in the Lewis structure for the compound YW₂?

Quizplus · Accepted Answer

The compound YW₂ is a fictional representation, but we can deduce the number of "dots" (valence electrons) in its Lewis structure by interpreting the symbols as elements from the periodic table. Y (Yttrium) has 2 valence electrons, W (Tungsten) has 6, S (Sulfur) has 6, U (Uranium) has 6, and B (Boron) has 3. Given the subscript numbers next to each element symbol, we calculate the total valence electrons as follows: Y(2) + W(6) + S(6*1) + U(6*1) + B(3*12) = 2 + 6 + 6 + 6 + 36 = 56. However, the question seems to be misinterpreted as it doesn't match standard chemical notation or a recognizable compound, leading to confusion about the "dots" calculation. The correct approach to finding the number of dots (valence electrons) in a Lewis structure involves counting all the valence electrons from each atom in the molecule. Without a real chemical formula, we cannot accurately determine the number of dots.

Four Hypothetical Elements, A, B, C and D, Have the Following