$\frac{x^{2}-1}{3 x+3} \cdot \frac{x+3}{x-1}$

A) $\frac{x+3}{3}$

B) $x+3$

C) $\frac{1}{3}$

D) $\frac{(x+3)(x-1)}{3(x-1)}$

Name: $\frac{x^{2}-1}{3 x+3} \cdot \frac{x+3}{x-1}$ A) $\frac{x+3}{3}$ B) $x+3$ C) $\frac{1}{3}$ D) $\frac{(x+3)(x-1)}{3(x-1)}$
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Question

$\frac{x^{2}-1}{3 x+3} \cdot \frac{x+3}{x-1}$

A) $\frac{x+3}{3}$

B) $x+3$

C) $\frac{1}{3}$

D) $\frac{(x+3)(x-1)}{3(x-1)}$

Quizplus · Accepted Answer

The expression simplifies by factoring and canceling common terms. Factor $x^2-1$ as $(x+1)(x-1)$ and $3x+3$ as $3(x+1)$. The expression becomes $\frac{(x+1)(x-1)}{3(x+1)} \cdot \frac{x+3}{x-1}$. Cancel $(x+1)$ and $(x-1)$ to get $\frac{x+3}{3}$.

x2−13x+3⋅x+3x−1\frac{x^{2}-1}{3 x+3} \cdot \frac{x+3}{x-1}3x+3x2−1​⋅x−1x+3​ A) x+33\frac{x+3}{3}3x+3​ B) x+3x+3x+3 C) 13\frac{1}{3}31​ D) (x+3)(x−1)3(x−1)\frac{(x+3)(x-1)}{3(x-1)}3(x−1)(x+3)(x−1)​

$\frac{x^{2}-1}{3 x+3} \cdot \frac{x+3}{x-1}$ A) $\frac{x+3}{3}$ B) $x+3$ C) $\frac{1}{3}$ D) $\frac{(x+3)(x-1)}{3(x-1)}$