$\frac{x-6}{(x+2)^{2}} \cdot \frac{x^{2}-4 x-12}{(x-6)^{2}}$

A) $\frac{1}{x+2}$

B) $\frac{x-6}{x+2}$

C) $\frac{1}{x-6}$

D) $x+2$

Name: $\frac{x-6}{(x+2)^{2}} \cdot \frac{x^{2}-4 x-12}{(x-6)^{2}}$ A) $\frac{1}{x+2}$ B) $\frac{x-6}{x+2}$ C) $\frac{1}{x-6}$ D) $x+2$
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Question

$\frac{x-6}{(x+2)^{2}} \cdot \frac{x^{2}-4 x-12}{(x-6)^{2}}$

A) $\frac{1}{x+2}$

B) $\frac{x-6}{x+2}$

C) $\frac{1}{x-6}$

D) $x+2$

Quizplus · Accepted Answer

The given expression simplifies to $\frac{1}{x+2}$ after factoring and canceling out common terms.

x−6(x+2)2⋅x2−4x−12(x−6)2\frac{x-6}{(x+2)^{2}} \cdot \frac{x^{2}-4 x-12}{(x-6)^{2}}(x+2)2x−6​⋅(x−6)2x2−4x−12​ A) 1x+2\frac{1}{x+2}x+21​ B) x−6x+2\frac{x-6}{x+2}x+2x−6​ C) 1x−6\frac{1}{x-6}x−61​ D) x+2x+2x+2

$\frac{x-6}{(x+2)^{2}} \cdot \frac{x^{2}-4 x-12}{(x-6)^{2}}$ A) $\frac{1}{x+2}$ B) $\frac{x-6}{x+2}$ C) $\frac{1}{x-6}$ D) $x+2$