Solve for the specified variable
-$S=\frac{H}{m t_{1}-m t_{2}}$ for $m$

A) $m=\frac{S H}{t_{1}-t_{2}}$

B) $m=\frac{H+\mathrm{St}_{2}}{\mathrm{St}_{1}}$

C) $m=\frac{H}{S\left(t_{1}-t_{2}\right)}$

D) $m=\frac{H}{S_{1}-t_{2}}$

Question

Solve for the specified variable
-$S=\frac{H}{m t_{1}-m t_{2}}$ for $m$

A) $m=\frac{S H}{t_{1}-t_{2}}$

B) $m=\frac{H+\mathrm{St}_{2}}{\mathrm{St}_{1}}$

C) $m=\frac{H}{S\left(t_{1}-t_{2}\right)}$

D) $m=\frac{H}{S_{1}-t_{2}}$

Quizplus · Accepted Answer

To solve for $m$, we start with the given equation $S=\frac{H}{m t_{1}-m t_{2}}$. Multiplying both sides by $m t_{1}-m t_{2}$ and then dividing by $S$ gives $m(t_{1}-t_{2}) = \frac{H}{S}$. Finally, solving for $m$ gives $m = \frac{H}{S(t_{1}-t_{2})}$.

Solve for the Specified Variable - S=Hmt1−mt2S=\frac{H}{m t_{1}-m t_{2}}S=mt1​−mt2​H​ For mmm A) m=SHt1−t2m=\frac{S H}{t_{1}-t_{2}}m=t1​−t2​SH​

Solve for the Specified Variable
- $S=\frac{H}{m t_{1}-m t_{2}}$ For $m$ A) $m=\frac{S H}{t_{1}-t_{2}}$