Solve for the specified variable
-$S=\frac{H}{m\left(t_{1}-t_{2}\right)}$ for $t_{2}$

A) $t_{2}=\frac{\text { Smt }_{1}-H}{m}$

B) $t_{2}=\frac{m t_{1}-\mathrm{SH}}{\mathrm{Sm}}$

C) $t_{2}=\frac{H-S_{t} 1}{S m}$

D) $\mathrm{t}_{2}=\frac{\mathrm{Smt}_{1}-\mathrm{H}}{\mathrm{Sm}}$

Question

Solve for the specified variable
-$S=\frac{H}{m\left(t_{1}-t_{2}\right)}$ for $t_{2}$

A) $t_{2}=\frac{\text { Smt }_{1}-H}{m}$

B) $t_{2}=\frac{m t_{1}-\mathrm{SH}}{\mathrm{Sm}}$

C) $t_{2}=\frac{H-S_{t} 1}{S m}$

D) $\mathrm{t}_{2}=\frac{\mathrm{Smt}_{1}-\mathrm{H}}{\mathrm{Sm}}$

Quizplus · Accepted Answer

To solve for $t_2$, we start with the given equation $S=\frac{H}{m(t_1-t_2)}$. Multiplying both sides by $m(t_1-t_2)$ gives $Sm(t_1-t_2) = H$. Expanding the left side, we get $Smt_1 - Smt_2 = H$. Rearranging for $t_2$, we have $Smt_2 = Smt_1 - H$, and dividing both sides by $Sm$ gives $t_2 = \frac{Smt_1 - H}{Sm}$, which matches choice D.

Solve for the Specified Variable - S=Hm(t1−t2)S=\frac{H}{m\left(t_{1}-t_{2}\right)}S=m(t1​−t2​)H​ For t2t_{2}t2​ A) t2= Smt 1−Hmt_{2}=\frac{\text { Smt }_{1}-H}{m}t2​=m Smt 1​−H​

Solve for the Specified Variable
- $S=\frac{H}{m\left(t_{1}-t_{2}\right)}$ For $t_{2}$ A) $t_{2}=\frac{\text { Smt }_{1}-H}{m}$