Given $f(x)=x^{2}-18 x+70$, find all values for $x$ for which $f(x) \geq 0$.
A) $[9-\sqrt{11}, 9+\sqrt{11}]$
B) $(-\infty,-\sqrt{11}] \cup[\sqrt{11}, \infty)$
C) $(-\infty, 9-\sqrt{11}] \cup[9+\sqrt{11}, \infty)$
D) $(-\infty, 9-\sqrt{11}) \cup(9+\sqrt{11}, \infty)$

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The Answer of Given $f(x)=x^{2}-18 x+70$, find all values for $x$ for which $f(x) \geq 0$.
A) $[9-\sqrt{11}, 9+\sqrt{11}]$
B) $(-\infty,-\sqrt{11}] \cup[\sqrt{11}, \infty)$
C) $(-\infty, 9-\sqrt{11}] \cup[9+\sqrt{11}, \infty)$
D) $(-\infty, 9-\sqrt{11}) \cup(9+\sqrt{11}, \infty)$

Given f(x)=x2−18x+70f(x)=x^{2}-18 x+70f(x)=x2−18x+70 , Find All Values For xxx For Which f(x)≥0f(x) \geq 0f(x)≥0

Given $f(x)=x^{2}-18 x+70$ , Find All Values For $x$ For Which $f(x) \geq 0$