Given $f(x)=\frac{x-8}{x+3}$, find all values for $x$ for which $f(x)

Name: Given $f(x)=\frac{x-8}{x+3}$, find all values for $x$ for which $f(x)<0$. A) $(-3,8)$ B) $(8, \infty)$ C) $(-\infty,-3) \cup(8, \infty)$ D) $(-\infty,-3)$
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Question

Given $f(x)=\frac{x-8}{x+3}$, find all values for $x$ for which $f(x)<0$.
A) $(-3,8)$
B) $(8, \infty)$
C) $(-\infty,-3) \cup(8, \infty)$
D) $(-\infty,-3)$

Quizplus · Accepted Answer

The function $f(x)=\frac{x-8}{x+3}$ is negative when the numerator and denominator have opposite signs. This occurs when $x<8$ (numerator negative) and $x>-3$ (denominator positive), so the solution is $x \in (-3,8)$.

Given f(x)=x−8x+3f(x)=\frac{x-8}{x+3}f(x)=x+3x−8​ , Find All Values For xxx For Which f(x)<0f(x)<0f(x)<0 A) (−3,8)(-3,8)(−3,8)

Given $f(x)=\frac{x-8}{x+3}$ , Find All Values For $x$ For Which $f(x)<0$
A) $(-3,8)$