Factor.
-$y^{2}+0.4 y+0.04$
A) $\left(y^{2}+0.2\right)^{2}$
B) $(y+0.4)^{2}$
C) $y(y+0.4)$
D) $(y+0.2)^{2}$

Name: Factor. -$y^{2}+0.4 y+0.04$ A) $\left(y^{2}+0.2\right)^{2}$ B) $(y+0.4)^{2}$ C) $y(y+0.4)$ D) $(y+0.2)^{2}$
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Question

Quizplus · Accepted Answer

The given expression is a perfect square trinomial. It can be factored into $(y+0.2)^{2}$ because $(0.2)^2 = 0.04$ and $2 \cdot 0.2 \cdot y = 0.4y$.

Factor - y2+0.4y+0.04y^{2}+0.4 y+0.04y2+0.4y+0.04 A) (y2+0.2)2\left(y^{2}+0.2\right)^{2}(y2+0.2)2 B) (y+0.4)2(y+0.4)^{2}(y+0.4)2 C) y(y+0.4)y(y+0.4)y(y+0.4) D) (y+0.2)2(y+0.2)^{2}(y+0.2)2

Factor
- $y^{2}+0.4 y+0.04$ A) $\left(y^{2}+0.2\right)^{2}$ B) $(y+0.4)^{2}$ C) $y(y+0.4)$ D) $(y+0.2)^{2}$