Factor.
-$t^{2}+1.2 t+0.35$
A) $(t+1.2)(t+0.35)$
B) $(t+0.5)(t+0.7)$
C) Prime
D) $(t+0.6)^{2}$

Name: Factor. -$t^{2}+1.2 t+0.35$ A) $(t+1.2)(t+0.35)$ B) $(t+0.5)(t+0.7)$ C) Prime D) $(t+0.6)^{2}$
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Question

Quizplus · Accepted Answer

The correct factorization of $t^{2}+1.2t+0.35$ is $(t+0.5)(t+0.7)$, because $0.5 + 0.7 = 1.2$ and $0.5 \times 0.7 = 0.35$, which matches the original equation's middle term and constant term, respectively.

Factor - t2+1.2t+0.35t^{2}+1.2 t+0.35t2+1.2t+0.35 A) (t+1.2)(t+0.35)(t+1.2)(t+0.35)(t+1.2)(t+0.35) B) (t+0.5)(t+0.7)(t+0.5)(t+0.7)(t+0.5)(t+0.7) C) Prime D) (t+0.6)2(t+0.6)^{2}(t+0.6)2

Factor
- $t^{2}+1.2 t+0.35$ A) $(t+1.2)(t+0.35)$ B) $(t+0.5)(t+0.7)$ C) Prime
D) $(t+0.6)^{2}$