Factor completely.
-$8 x^{2}-28 x-16$
A) $4(2 x+1)(x-4)$
B) $4(2 x-1)(x+4)$
C) $(2 x-1)(4 x+16)$
D) $(8 x-4)(x+4)$

Question

Quizplus · Accepted Answer

The correct factorization of $8x^2 - 28x - 16$ is $4(2x+1)(x-4)$. This can be found by first factoring out the greatest common factor, which is 4, giving $4(2x^2 - 7x - 4)$. Then, using the quadratic formula or factoring by grouping, we find the factors to be $2x + 1$ and $x - 4$.

Factor Completely 8x2−28x−168 x^{2}-28 x-168x2−28x−16 A) 4(2x+1)(x−4)4(2 x+1)(x-4)4(2x+1)(x−4) B) 4(2x−1)(x+4)4(2 x-1)(x+4)4(2x−1)(x+4) C) (2x−1)(4x+16)(2 x-1)(4 x+16)(2x−1)(4x+16)

Factor Completely $8 x^{2}-28 x-16$ A) $4(2 x+1)(x-4)$ B) $4(2 x-1)(x+4)$ C) $(2 x-1)(4 x+16)$