Factor completely.
-$25 x^{2} y^{2}-70 x y+49$
A) $(5 x y-7)^{2}$
B) $(5 x y-7)(5 x y+7)$
C) $(5 x y+7)^{2}$

D) Prime

Name: Factor completely. -$25 x^{2} y^{2}-70 x y+49$ A) $(5 x y-7)^{2}$ B) $(5 x y-7)(5 x y+7)$ C) $(5 x y+7)^{2}$ D) Prime
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Question

Factor completely.
-$25 x^{2} y^{2}-70 x y+49$
A) $(5 x y-7)^{2}$
B) $(5 x y-7)(5 x y+7)$
C) $(5 x y+7)^{2}$

D) Prime

Quizplus · Accepted Answer

This expression is a perfect square trinomial, factoring into $(5xy - 7)^2$, because $(5xy)^2 = 25x^2y^2$, $-2(5xy)(7) = -70xy$, and $7^2 = 49$.

Factor Completely 25x2y2−70xy+4925 x^{2} y^{2}-70 x y+4925x2y2−70xy+49 A) (5xy−7)2(5 x y-7)^{2}(5xy−7)2 B) (5xy−7)(5xy+7)(5 x y-7)(5 x y+7)(5xy−7)(5xy+7)

Factor Completely $25 x^{2} y^{2}-70 x y+49$ A) $(5 x y-7)^{2}$ B) $(5 x y-7)(5 x y+7)$