Solve.
-From a $\frac{7}{8}-\mathrm{lb}$ package of ground beef, $\mathrm{a} \frac{1}{3}-\mathrm{lb}$ hamburger was made. How much ground beef is left in the package?
A) $\frac{5}{6} \mathrm{lb}$
B) $\frac{1}{4} \mathrm{lb}$
C) $\frac{1}{2} \mathrm{lb}$
D) $\frac{13}{24} \mathrm{lb}$

Question

Quizplus · Accepted Answer

To find the remaining ground beef, subtract $\frac{1}{3}$ lb from $\frac{7}{8}$ lb. Convert to a common denominator: $\frac{7}{8} = \frac{21}{24}$ and $\frac{1}{3} = \frac{8}{24}$. Subtract: $\frac{21}{24} - \frac{8}{24} = \frac{13}{24}$.

Solve -From A \frac{7}{8}-\mathrm{lb} 78−lb\frac{7}{8}-\mathrm{lb}87​−lb Package of Ground Beef a13−lb\mathrm{a} \frac{1}{3}-\mathrm{lb}a31​−lb Hamburger Was Made

Solve
-From A \frac{7}{8}-\mathrm{lb} $\frac{7}{8}-\mathrm{lb}$ Package of Ground Beef $\mathrm{a} \frac{1}{3}-\mathrm{lb}$ Hamburger Was Made