Solve. Write a mixed numeral for the answer.
-A painter used $8 \frac{5}{6}$ gallons of paint to paint the front of a house and another $8 \frac{7}{9}$ gallons to paint the back. How much paint did he use in total?
A) $16 \frac{47}{54} \mathrm{gal}$
B) $17 \frac{11}{18} \mathrm{gal}$
C) $16 \frac{87}{54}$ gal
D) $16 \frac{11}{18} \mathrm{gal}$

Question

Quizplus · Accepted Answer

To find the total paint used, add $8 \frac{5}{6}$ and $8 \frac{7}{9}$. First, convert the fractions to have a common denominator, which is 54 (LCM of 6 and 9). So, $8 \frac{5}{6} = 8 \frac{45}{54}$ and $8 \frac{7}{9} = 8 \frac{42}{54}$. Adding these gives $16 \frac{87}{54}$. Simplifying the fraction $\frac{87}{54}$ gives $1 \frac{33}{54}$, which simplifies further to $1 \frac{11}{18}$ when divided by 3. Therefore, the total is $17 \frac{11}{18}$ gallons.

Solve Write a Mixed Numeral for the Answer 8568 \frac{5}{6}865​ Gallons of Paint to Paint the Front of a House

Solve Write a Mixed Numeral for the Answer $8 \frac{5}{6}$ Gallons of Paint to Paint the Front of a House