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Prove That cos⁡2θ=1−tan⁡2θ1+tan⁡2θ\cos 2 \theta=\frac{1-\tan^{2} \theta}{1+\tan^{2} \theta}

Question 68

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Prove that cos⁡2θ=1−tan⁡2θ1+tan⁡2θ\cos 2 \theta=\frac{1-\tan^{2} \theta}{1+\tan^{2} \theta} .

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