If $A$ and $B$ are the two acute angles of a right triangle, show that $\frac{\sin (A-B)}{\tan A-\tan B}=\frac{1}{2} \sin 2 A$.

Name: If $A$ and $B$ are the two acute angles of a right triangle, show that $\frac{\sin (A-B)}{\tan A-\tan B}=\frac{1}{2} \sin 2 A$.
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The Answer of If $A$ and $B$ are the two acute angles of a right triangle, show that $\frac{\sin (A-B)}{\tan A-\tan B}=\frac{1}{2} \sin 2 A$.

If AAA And BBB Are the Two Acute Angles of a Right Triangle, Show

If $A$ And $B$ Are the Two Acute Angles of a Right Triangle, Show