Suppose that there are two products with the same first product time. However, product A has an improvement rate of 10% while product B has an improvement rate of 20%. How much longer will it take to make the 10ᵗʰ unit of product A compared to product B?
A) Both will have the identical time for the 10ᵗʰ unit.
B) A will take 48% more time.
C) A will take 48% less time.
D) A will take 23% less time.
E) none of the above

Question

Quizplus · Accepted Answer

Let's assume the first unit takes x hours for both products to manufacture.

For product A, the time taken to manufacture the 10th unit can be calculated as:
x + (10-1)*(10% of x) = x + 0.9x = 1.9x hours

For product B, the time taken to manufacture the 10th unit can be calculated as:
x + (10-1)*(20% of x) = x + 1.8x = 2.8x hours

Therefore, the ratio of time taken to manufacture the 10th unit of A to B = $ \frac{1.9x}{2.8x} $ = 0.6785 or approximately 67.85%.

This implies that A would take about 48% (100-67.85) more time to manufacture the 10th unit than B. Hence, the answer is B.

Suppose That There Are Two Products with the Same First