A methods and measurements analyst needs to develop a time standard for a certain task. In a preliminary study, he observed one of his workers perform this task five times, with the following results: $$\begin{array} { | l | c | c | c | c | c | }
\hline \text { Observation } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Time(Seconds) } & 84 & 76 & 80 & 84 & 76 \
\hline
\end{array}$$ What is the normal time for this task if the employee worked at a 25 percent faster pace than average?
A) 80 seconds
B) 96 seconds
C) 100 seconds
D) 120 seconds
E) 125 seconds

Question

A methods and measurements analyst needs to develop a time standard for a certain task. In a preliminary study, he observed one of his workers perform this task five times, with the following results: $$\begin{array} { | l | c | c | c | c | c | } 
\hline \text { Observation } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Time(Seconds) } & 84 & 76 & 80 & 84 & 76 \
\hline
\end{array}$$ What is the normal time for this task if the employee worked at a 25 percent faster pace than average?
A) 80 seconds
B) 96 seconds
C) 100 seconds
D) 120 seconds
E) 125 seconds

Quizplus · Accepted Answer

The normal time is the average time taken to perform the task, which is (84 + 76 + 80 + 84 + 76) / 5 = 80 seconds. If the employee worked at a 25 percent faster pace than average, the normal time would be reduced by 25 percent, which is 80 * 0.75 = 60 seconds.

A Methods and Measurements Analyst Needs to Develop a Time