A methods and measurements analyst for Timepiece, Inc., needs to develop a time standard for the task of attaching a watch to a wristband. In a preliminary study, he observed one of his workers perform this task five times, with the following results: $$\begin{array} { | l | c | c | c | c | c | }
\hline \text { Observation } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Time(Seconds) } & 27 & 19 & 20 & 21 & 13 \
\hline
\end{array}$$ What is the standard time for this task if the employee worked at a 20 percent faster pace than average, and an allowance of 20 percent of job time is used?
A) 4.5 seconds
B) 5 seconds
C) 20 seconds
D) 28.8 seconds
E) 100 seconds

Question

A methods and measurements analyst for Timepiece, Inc., needs to develop a time standard for the task of attaching a watch to a wristband. In a preliminary study, he observed one of his workers perform this task five times, with the following results: $$\begin{array} { | l | c | c | c | c | c | } 
\hline \text { Observation } & 1 & 2 & 3 & 4 & 5 \
\hline \text { Time(Seconds) } & 27 & 19 & 20 & 21 & 13 \
\hline
\end{array}$$ What is the standard time for this task if the employee worked at a 20 percent faster pace than average, and an allowance of 20 percent of job time is used?
A) 4.5 seconds
B) 5 seconds
C) 20 seconds
D) 28.8 seconds
E) 100 seconds

Quizplus · Accepted Answer

To find the standard time for the task, we need to use the observed times to calculate the mean observed time (x̄), including the allowance (A) and the worker's pace rating (PR):

x̄ = (Σx + A)/(n × PR)

where Σx is the sum of the observed times, n is the number of observations (in this case, 5), and PR is the pace rating as a decimal (in this case, 1.2 for a 20% faster pace).

Σx = 27 + 19 + 20 + 21 + 13 = 100

A = 0.2(x̄) = 0.2(20) = 4

x̄ = (100 + 4)/(5 × 1.2) = 21.67 seconds

Therefore, the standard time for the task is 21.67 seconds, and the best answer choice is D.

A Methods and Measurements Analyst for Timepiece, Inc What Is the Standard Time for This Task If the Develop