The conversion of glucose-1-phosphate to glucose-6-phosphate by the enzyme phosphoglucomutase has a △G°' of -7.6 kJ/mol.Calculate the equilibrium constant for this reaction at 298 K and a pH of 7.(R = 8.315 J/K-mol)
A)0.003
B)0.047
C)1.00
D)21

Question

Quizplus · Accepted Answer

We can use the equation △G°' = -RTlnK to calculate the equilibrium constant (K) for the reaction. 
Plugging in the given values, we get: 
-7.6 kJ/mol = -(8.315 J/K-mol)(298 K)lnK
Solving for lnK, we get: 
lnK = 2.723
Taking the antilog of both sides, we get: 
K = e^2.723
K ≈ 21 
Thus, the answer is D.

The Conversion of Glucose-1-Phosphate to Glucose-6-Phosphate by the Enzyme Phosphoglucomutase