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Computing
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Concepts of Database Management Study Set 2
Quiz 6: Database Design 2: Design Method
Path 4
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Question 1
True/False
The basic relationships among entities are: one-to-many, many-to-many, and one-to-one.
Question 2
True/False
A surrogate key is a primary key that consists of a column that uniquely identifies an entity.
Question 3
True/False
If you find that more than one table in your cumulative design has the same primary key, you should combine the tables to form a new table.
Question 4
True/False
A weak entity is an entity that depends on another entity for its own existence.
Question 5
True/False
When the user views are not clearly defined, you should consider each stated requirement as a separate user view.
Question 6
True/False
After you have completed the first two steps for a given user view, you can merge the results into the cumulative design.
Question 7
True/False
The first substep in representing the user view as a collection of tables is to determine entities and create a table for each.
Question 8
True/False
If no unique identifier is available for an entity, you can go without one.
Question 9
True/False
A foreign key is a column or collection of columns in one table that is required to match the value of the primary key for some row in another table, or be null.
Question 10
True/False
If each employee works in a single department, and each department has only one employee, the relationship between employees and departments is a one-to-many relationship.
Question 11
True/False
A design that supports all user views is called a constructive design.
Question 12
True/False
The simplest way to implement a one-to-one relationship is to treat it as a one-to-many relationship.
Question 13
True/False
The first step in creating a user view is to normalize the collection of tables.
Question 14
True/False
You create a many-to-many relationship by creating a new table whose primary key is the combination of the primary keys of the original tables.
Question 15
True/False
When combining third normal form tables, the resulting table will not be in third normal form when a column A in one user view determines a column B in a second user view, yet column A is not a column in the second user view.