Using the following equation for the combustion of octane, calculate the heat of reaction for 100.0 g of octane. The molar mass of octane is 114.33 g mol^-1. 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O Δ_rH°= -11018 kJ

Question

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The heat of reaction for 100.0 g of octane is calculated by first determining the moles of octane (100.0 g / 114.33 g/mol = 0.874 mol). Since the reaction involves 2 moles of octane releasing -11018 kJ, 0.874 moles will release (0.874 / 2) * -11018 kJ = -4820.37 kJ, which is approximately 4.82 × 10³ kJ.

Using the Following Equation for the Combustion of Octane, Calculate