Using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (C₆H₆). The molar mass of benzene is 78.11 g mol^-1 2C₆H₆(l)+ 15O₂(g)→ 12CO₂(g)+ 6H₂O(g)Δ_rH°= -6278 kJ

Question

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The combustion of 2 moles of benzene releases 6278 kJ. First, calculate the moles of benzene in 24.3 g: 24.3 g / 78.11 g/mol = 0.311 moles. Since 2 moles release 6278 kJ, 0.311 moles will release (6278 kJ / 2) * 0.311 = 977 kJ.

Using the Following Thermochemical Equation, Determine the Amount of Heat