The specific heat capacity of liquid water is 4.184 J g^-1 K^-1. How many joules of heat are needed to raise the temperature of 6.00 g of water from 36.0 °C to 75.0 °C?

Question

Quizplus · Accepted Answer

The amount of heat required to raise the temperature of a substance is given by the equation:Q = m * c * ΔTwhere:Q is the heat energy in joules (J)m is the mass of the substance in grams (g)c is the specific heat capacity of the substance in joules per gram per degree Celsius (J g^-1 °C^-1)ΔT is the change in temperature in degrees Celsius (°C)In this problem, we have:m = 6.00 gc = 4.184 J g^-1 °C^-1ΔT = 75.0 °C - 36.0 °C = 39.0 °CSubstituting these values into the equation, we get:Q = 6.00 g * 4.184 J g^-1 °C^-1 * 39.0 °C = 978 JTherefore, the correct answer is B) 978 J.

The Specific Heat Capacity of Liquid Water Is 4