At 1.0133 bar, the heat of sublimation of gallium is 277 kJ mol^-1 and the heat of vaporization is 271 kJ mol^-1. To the correct number of significant figures, how much heat is required to melt 5.50 mol of gallium at 1.0133 bar?

Question

Quizplus · Accepted Answer

The heat of fusion is the difference between the heat of sublimation and the heat of vaporization. Thus, it is 277 kJ/mol - 271 kJ/mol = 6 kJ/mol. For 5.50 mol, the heat required is 5.50 mol * 6 kJ/mol = 33 kJ.

At 10133 Bar, the Heat of Sublimation of Gallium Is 277