The decomposition of N₂O₅ in solution in carbon tetrachloride proceeds via the reaction 2N₂O₅(soln) → 4NO₂(soln) + O₂(soln)
The reaction is first order and has a rate constant of 4.82 × 10^-3 s^-1 at 64 °C. If the reaction is initiated with 0.058 mol in a 1.00 L vessel, how many moles remain after 151 s?

Question

Quizplus · Accepted Answer

We will use the integrated rate law for a first-order reaction, which is:

ln([A]/[A]0) = -kt

Where [A] is the concentration of the reactant at a given time, [A]0 is the initial concentration, k is the rate constant, and t is time.

Substituting the given values, we get:

ln([A]/0.058) = -4.82 × 10^-3 × 151

Solving for [A], we get:

[A] = 0.028 mol/L

Therefore, the number of moles remaining after 151 s is 0.028 mol (Option C).

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The Decomposition of N₂O₅ in Solution in Carbon Tetrachloride Proceeds