The K_p for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g) + Cl₂(g) → COCl₂(g)
In an equilibrium mixture of the three gases, P_CO = = 2.22 × 10^-4 bar. The partial pressure of the product, phosgene (COCl₂) , is ________ bar.

Question

The K_p for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g) + Cl₂(g) → COCl₂(g)
In an equilibrium mixture of the three gases, P_CO =

The K<sub>p</sub> for the reaction below is 1.49 × 10<sup>8</sup> bar<sup>-1</sup> at 100.0 °C: CO(g) + Cl<sub>2</sub>(g) → COCl<sub>2</sub>(g) In an equilibrium mixture of the three gases, P<sub>CO</sub> = = 2.22 × 10<sup>-4</sup> bar. The partial pressure of the product, phosgene (COCl<sub>2</sub>) , is ________ bar. A) 7.34 B) 3.02 × 10<sup>15</sup> C) 3.31 × 10<sup>-16</sup> D) 3.31 × 10<sup>4</sup> E) 6.67 × 10<sup>11</sup>

= 2.22 × 10^-4 bar. The partial pressure of the product, phosgene (COCl₂) , is ________ bar.

Quizplus · Accepted Answer

The Answer of The K_p for the reaction below is 1.49 × 10⁸ bar^-1 at 100.0 °C: CO(g)+ Cl₂(g)→ COCl₂(g) In an equilibrium mixture of the three gases, P_CO = = 2.22 × 10^-4 bar. The partial pressure of the product, phosgene (COCl₂), is ________ bar.

The Kp for the Reaction Below Is 1

The K_p for the Reaction Below Is 1