How many moles of PCl5 will be produced if .331 moles of P4 is reacted with an excess of Cl2 using the following equation. P4(s) + 10 Cl2(g) → 4 PCl5(g)
A) .331 mol
B) .662 mol
C) .993 mol
D) 1.324 mol
E) 1.655 mol
Correct Answer:
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