Using the following equation for the combustion of octane,calculate the amount of moles of oxygen that reacts with 100.0 g of octane.The molar mass of octane is 114.33 g/mole.The molar mass of carbon dioxide is 44.0095 g/mole. 2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O ΔH°_rxn= -11018 kJ

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First, calculate the moles of octane: 100.0 g / 114.33 g/mol = 0.8749 moles. According to the balanced equation, 2 moles of octane react with 25 moles of oxygen. Therefore, 0.8749 moles of octane will react with (25/2) * 0.8749 = 10.93 moles of oxygen.

Using the Following Equation for the Combustion of Octane,calculate the Amount