Solved

The Decomposition of in Solution in Carbon Tetrachloride

Question 112

Multiple Choice

The decomposition of The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M in solution in carbon tetrachloride proceeds via the reaction 2 The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M (soln) → The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M (soln) + The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M (soln)
The reaction is first order and has a rate constant of 4.82 × The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s?


A) 0.055 M
B) 0.060 M
C) 0.028 M
D) 12 M
E) 2.0 × The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2 (soln) → (soln) + (soln) The reaction is first order and has a rate constant of 4.82 × at 64°C.If the reaction is initiated with 0.058 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.055 M B) 0.060 M C) 0.028 M D) 12 M E) 2.0 × M M

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q102: For a particular first-order reaction,it takes 24

Q105: How many half-lives are required for the

Q109: decomposes</p></div><svg width=

Q110: If the concentration of a reactant is

Q111: Which of the following represents the equation

Q111: How many half-lives are required for the

Q113: How many half-lives are required for the

Q114: Given the following rate law,how does the

Q116: The isomerization of methylisonitrile to acetonitrile CH3NC(g)→

Q117: The rate constant for a zero-order reaction

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents