If the concentration of a reactant is 6.25%,how many half-lives has it gone through?

Name: If the concentration of a reactant is 6.25%,how many half-lives has it gone through?
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Question

Quizplus · Accepted Answer

To determine the number of half-lives, we need to use the following formula:
n = (log(Nf/Ni))/log(1/2)
where
n = number of half-lives
Nf = final concentration
Ni = initial concentration
Plugging in the values, we get:
n = (log(6.25/100))/log(1/2) = 3.98
Rounding off, we get 4 half-lives, which is option D.

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