Consider the reaction CH₄(g)+ H₂O(g)→ 3 H₂(g)+ CO(g).If 2.25 L of methane,measured at STP,react,how many liters of hydrogen will be produced if it is also measured at STP?

Question

Quizplus · Accepted Answer

At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. The given reaction is: CH4(g) + 2O2(g) → 3H2(g) + CO(g). From the balanced equation, 1 mole of CH4 produces 3 moles of H2. Given 2.25 L of CH4, we first find the moles of CH4: 2.25 L / 22.4 L/mol = 0.1 mol. Since 1 mole of CH4 produces 3 moles of H2, 0.1 mol of CH4 will produce 0.1 * 3 = 0.3 moles of H2. Therefore, the volume of H2 produced at STP = 0.3 moles * 22.4 L/mol = 6.75 L.

Consider the Reaction CH4(g)+ H2O(g)→ 3 H2(g)+ CO(g)

Consider the Reaction CH₄(g)+ H₂O(g)→ 3 H₂(g)+ CO(g)