In the reaction 2 AgI + HgI₂ → Ag₂HgI₄,2.00 g of AgI and 3.50 g of HgI₂ were used.What is the limiting reactant?

Question

Quizplus · Accepted Answer

To determine the limiting reactant, we need to compare the number of moles of each reactant used. Number of moles of AgI = 2.00 g / 234.77 g/mol = 0.00852 mol Number of moles of HgI₂ = 3.50 g / 628.01 g/mol = 0.00557 mol Since the number of moles of HgI₂ is less than the number of moles of AgI, HgI₂ is the limiting reactant. Therefore, option A is correct.

In the Reaction 2 AgI + HgI2 → Ag2HgI4,2

In the Reaction 2 AgI + HgI₂ → Ag₂HgI₄,2