How many molecules of HCl are formed when 50.0 g of water reacts according to the following balanced reaction? Assume excess ICl₃. 2 ICl₃ + 3 H₂O → ICl + HIO₃ + 5 HCl A)2.78 × 10²⁴molecules HCl B)1.67 × 10²⁴molecules HCl C)5.02 × 10²⁵molecules HCl D)6.09 × 10²⁵molecules HCl E)3.65 × 10²⁴molecules HCl

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Quizplus · Accepted Answer

50.0 g of water is 50.0 g / 18.02 g/mol = 2.77 mol of water. From the balanced reaction, we see that 3 mol of water react to produce 5 mol of HCl. Therefore, 2.77 mol of water will react to produce 2.77 mol * 5 mol HCl / 3 mol H2O = 4.62 mol of HCl. 4.62 mol of HCl is 4.62 mol * 6.022 * 10^23 molecules/mol = 2.78 * 10^24 molecules of HCl.

How Many Molecules of HCl Are Formed When 50