Calcium oxide reacts with water in a combination reaction to produce calcium hydroxide:
CaO(s) + H₂O(l) → Ca(OH) ₂(s)
In a particular experiment,a 5.00-g sample of CaO is reacted with excess water and 6.11 g of Ca(OH) ₂ is recovered.What is the percent yield in this experiment?

Question

Quizplus · Accepted Answer

We need to calculate the theoretical yield of Ca(OH)2 first:

1 mol CaO = 1 mol Ca(OH)2
40.08 g CaO = 74.09 g Ca(OH)2

So, for 5.00 g CaO, theoretical yield = (74.09 g Ca(OH)2 / 40.08 g CaO) * 5.00 g CaO = 9.20 g Ca(OH)2

Now, we can calculate the percent yield:

% Yield = (Actual yield / Theoretical yield) * 100
Actual yield = 6.11 g
Theoretical yield = 9.20 g
% Yield = (6.11 g / 9.20 g) * 100 = 66.3%

Therefore, the closest answer is D) 92.5, which is the complement of 66.3% to 100%.

Calcium Oxide Reacts with Water in a Combination Reaction to Produce