What is the oxidation number of the chromium atom in Na₂CrO₄?

Question

Quizplus · Accepted Answer

The oxidation numbers of sodium, sulfur, and oxygen are +1, -2, and -2 respectively. The sum of the oxidation numbers of all the atoms in a compound is equal to the overall charge of the compound, which is 0 in this case. Let x be the oxidation number of chromium. Then we have:
(+1) + (-2) + 12(-1) + (-2) + x + 14(-1) + (-2) = 0
Solving for x, we get:
x = +6
Therefore, the oxidation number of the chromium atom is +6, which corresponds to choice C.

What Is the Oxidation Number of the Chromium Atom in Na2CrO4

What Is the Oxidation Number of the Chromium Atom in Na₂CrO₄